# C++ Program to Check Whether a Number can be Express as Sum of Two Prime Numbers

In this example, we will learn a program to check if an integer (entered by the user) can be expressed as the sum of two prime numbers of all possible combinations with the use of functions.

To understand this example, you should have the knowledge of the following C++ programming topics:

## Sum of Two Prime Numbers

This program takes a positive integer from user and checks whether that number can be expressed as the sum of two prime numbers.

If the number can be expressed as sum of two prime numbers, the output shows the combination of the prime numbers.

To perform this task, a user-defined function is created to check prime number.

## Example: Program to Check Whether a Number can be Expressed as a Sum of Two Prime Numbers

```
# include <iostream>
using namespace std;
bool checkPrime(int n);
int main() {
int n, i;
bool flag = false;
cout << "Enter a positive integer: ";
cin >> n;
for(i = 2; i <= n/2; ++i) {
if (checkPrime(i)) {
if (checkPrime(n - i)) {
cout << n << " = " << i << " + " << n-i << endl;
flag = true;
}
}
}
if (!flag)
cout << n << " can't be expressed as sum of two prime numbers.";
return 0;
}
// Check prime number
bool checkPrime(int n)
{
int i;
bool isPrime = true;
// 0 and 1 are not prime numbers
if (n == 0 || n == 1) {
isPrime = false;
}
else {
for(i = 2; i <= n/2; ++i) {
if(n % i == 0) {
isPrime = false;
break;
}
}
}
return isPrime;
}
```

**Output 1**

Enter a positive integer: 34 34 = 3 + 31 34 = 5 + 29 34 = 11 + 23 34 = 17 + 17

##### Working

In this program, we use the `checkPrime()`

function to check whether a number is prime or not. In `main()`

, we take a number from the user and store it in the variable `n`.

We also initialize a `bool`

variable `flag` to `false`

. We use this variable to determine whether the input number can be expressed as the sum of two prime numbers. then iterate a loop from `i = 2`

to `i = n/2`

. In each iteration, we check whether `i` is a prime number or not.

If `i` is a prime, we check whether `n - i` is prime or not.

If `n - i` is also a prime, then we know that `n` can be expressed as the sum of two prime numbers `i` and `n - i`. So, we print the result on the screen and change the value of `flag` to `true`

. Otherwise, `flag` remains `false`

.

This process continues until the loop ends. If `flag` is still `false`

, then we know that `n` can't be expressed as the sum of two primes, and we print that message on the screen.

## Next Example

We hope that this Example helped you develop better understanding of the concept of "Sum of Two Prime Numbers" in C++.

**Keep Learning : )**

In the next Example, we will learn about C++ `Find the Sum of Natural Numbers using Recursion`

.