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C++ Program to Find G.C.D Using Recursion

C++ Program to Find G.C.D Using Recursion

In this example, we will learn a program to to find the sum of natural numbers by using a recursive function.

To understand this example, you should have the knowledge of the following C++ programming topics:


G.C.D Using Recursion

This program takes two positive integers from user and calculates "GCD" using recursion.

Visit this page to learn, how you can calculate GCD using loops.


Example: Program to Calculate H.C.F using recursion

#include <iostream>
using namespace std;
int hcf(int n1, int n2);

int main()
{
   int n1, n2;

   cout << "Enter two positive integers: ";
   cin >> n1 >> n2;

   cout << "H.C.F of " << n1 << " & " <<  n2 << " is: " << hcf(n1, n2);

   return 0;
}

int hcf(int n1, int n2)
{
    if (n2 != 0)
       return hcf(n2, n1 % n2);
    else 
       return n1;
}

Output 1

Enter two positive integers: 366 60
H.C.F of 366 and 60 is: 6

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In the next Example, we will learn about C++ Binary Number to Decimal and vice-versa.


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