C++ Program to Reverse a Number

Example: Program to Reverse an Integer

#include <iostream>
using namespace std;

int main() {
    int n, reversedNumber = 0, remainder;

    cout << "Enter an integer: ";
    cin >> n;

    while(n != 0) {
        remainder = n%10;
        reversedNumber = reversedNumber*10 + remainder;
        n /= 10;
    }

    cout << "Reversed Number = " << reversedNumber;

    return 0;
}

Output

Enter an integer: 12345
Reversed number = 54321

Working

This program takes an integer input from the user and stores it in variable n.

Then the while loop is iterated until n != 0 is false.

In each iteration, the remainder when the value of n is divided by 10 is calculated, reversedNumber is computed and the value of n is decreased 10 fold.

Let us see this process in greater detail:

1. In the first iteration of the loop,
   n = 12345
remainder 12345 % 10 = 5
reversedNumber = 0 * 10 + 5 = 5
2. In the second iteration of the loop,
   n = 1234
remainder 1234 % 10 = 4
reversedNumber = 5 * 10 + 4 = 54

And so on, until n == 0. Finally, the reversedNumber (which contains the reversed number) is printed on the screen.

Next Example

We hope that this Example helped you develop better understanding of the concept of "Find Reverse a Number" in C++.

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In the next Example, we will learn about C++ Program to Find Power of a Number.