C++ Program to Check Leap Year

Leap Year

All years which are perfectly divisible by 4 are leap years except for century years (years ending with 00) which is leap year only it is perfectly divisible by 400.

For example: 2012, 2004, 1968 etc are leap year but, 1971, 2006 etc are not leap year. Similarly, 1200, 1600, 2000, 2400 are leap years but, 1700, 1800, 1900 etc are not.

In this program below, user is asked to enter a year and this program checks whether the year entered by user is leap year or not.

Example 1: Program to Check if a year is leap year or not using only if-else statement.

#include <iostream>
using namespace std;

int main()
{
    int year;

    cout << "Enter a year: ";
    cin >> year;

    if (((year % 4 == 0) && (year % 100 != 0)|| (year % 400 == 0)))
    {
        cout << year << " is a leap year.";
    }
    else
    {
        cout << year << " is not a leap year.";
    }
    return 0;
}

Output 1

Enter a year: 2020
2010 is a leap year.

Output 2

Enter a year: 2018
2010 is not a leap year.

Example 2: Program to Check if a year is leap year or not using nested if-else statement

#include <iostream>
using namespace std;

int main()
{
    int year;

    cout << "Enter a year: ";
    cin >> year;

    if (year % 4 == 0)
    {
        if (year % 100 == 0)
        {
            if (year % 400 == 0)
                cout << year << " is a leap year.";
            else
                cout << year << " is not a leap year.";
        }
        else
            cout << year << " is a leap year.";
    }
    else
        cout << year << " is not a leap year.";

    return 0;
}

Output 1

Enter a year: 2010
2010 is not a leap year.

Output 2

Enter a year: 2012
2012 is a leap year.

Next Example

We hope that this Example helped you develop better understanding of the concept of "Find Leap Year" in C++.

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