C++ Program to Display Factors of a Number
In this example, we will learn a Program to Display Factors of a Number using for loop and if...else statement.
To understand this example, you should have the knowledge of the following C++ programming topics:
Factors of a Number
This program takes a positive integer from an user and displays all the factors of that number.
Example: Program to Display all Factors of a Number
#include <iostream>
using namespace std;
int main()
{
int n, i;
cout << "Enter a positive integer: ";
cin >> n;
cout << "Factors of " << n << " are: " << endl;
for(i = 1; i <= n; ++i)
{
if(n % i == 0)
cout << i << endl;
}
return 0;
}
Output 1
Enter a positive integer: 60 Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60
Working
In this program, an integer entered by user is stored in variable n. Then, for loop is executed with an initial condition i = 1
and checked whether n is perfectly divisible by i or not. If n is perfectly divisible by i then, i will be the factor of n.
In each iteration, the value of i is updated (increased by 1). This process goes until test condition i <= n
becomes false,i.e., this program checks whether number entered by user n is perfectly divisible by all numbers from 1 to n and all displays factors of that number.
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We hope that this Example helped you develop better understanding of the concept of "Display Factor of a Number" in C++.
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In the next Example, we will learn about C++ Program to Display Pyramids and Patterns
.