###### C++ Structures

C++ Program to Add Two Distances (in inch-feet) System Using Structures

# C++ Program to Add Two Distances (in inch-feet) Using Structures

In this example, we will learn to Add Two Distances (in inch-feet) Using Structures.

To understand this example, you should have the knowledge of the following C++ programming topics:

## Example: Program to Add Distances Using Structures

``````#include <iostream>
using namespace std;

struct Distance{
int feet;
float inch;
}d1 , d2, sum;

int main()
{
cout << "Enter 1st distance," << endl;
cout << "Enter feet: ";
cin >> d1.feet;
cout << "Enter inch: ";
cin >> d1.inch;

cout << "\nEnter information for 2nd distance" << endl;
cout << "Enter feet: ";
cin >> d2.feet;
cout << "Enter inch: ";
cin >> d2.inch;

sum.feet = d1.feet+d2.feet;
sum.inch = d1.inch+d2.inch;

// changing to feet if inch is greater than 12
if(sum.inch > 12)
{
++ sum.feet;
sum.inch -= 12;
}

cout << endl << "Sum of distances = " << sum.feet << " feet  " << sum.inch << " inches";
return 0;
}``````

Output

```Enter 1st distance,
Enter feet: 6
Enter inch: 3.4

Enter information for 2nd distance
Enter feet: 5
Enter inch: 10.2

Sum of distances = 12 feet  1.6 inches```

## working

In this program, a structure `Distance` containing two data members (inch and feet) is declared to store the distance in inch-feet system.

Here, two structure variables d1 and d2 are created to store the distance entered by the user. And, the sum variables stores the sum of the distances.

The `if..else` statement is used to convert inches to feet if the value of inch of sum variable is greater than 12.

## Next Example

We hope that this Example helped you develop better understanding of the concept of "Add Two Distances (in inch-feet system) using Structures" in C++.

Keep Learning : )

In the next Example, we will learn about C++ `Add Two Complex Numbers by Passing Structure to a Function`.